(58x(-0.4x^2))-(3x+12)=0

Solution for (58x(-0.4x^2))-(3x+12)=0 equation:

(58x(-0.4x^2))-(3x+12)=0

We get rid of parentheses

(58x(-0.4x^2))-3x-12=0


We calculate terms in parentheses: +(58x(-0.4x^2)), so:

58x(-0.4x^2)

We multiply parentheses

0x^2

We add all the numbers together, and all the variables

x^2

Back to the equation:

+(x^2)


a = 1; b = -3; c = -12;
Δ = b2-4ac
Δ = -32-4·1·(-12)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{57}}{2*1}=\frac{3-\sqrt{57}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{57}}{2*1}=\frac{3+\sqrt{57}}{2}
$